9n^2+48n+63=0

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Solution for 9n^2+48n+63=0 equation: 



9n^2+48n+63=0

a = 9; b = 48; c = +63;
Δ = b2-4ac
Δ = 482-4·9·63
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$


$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(48)-6}{2*9}=\frac{-54}{18}
=-3
$


$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(48)+6}{2*9}=\frac{-42}{18}
=-2+1/3
$

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